Semester : SEMESTER 4
Subject : Measurements and Instrumentation
Year : 2018
Term : MARCH
Scheme : 2015 Full Time
Course Code : EE 208
Page:12
From the principle of conservation of energy,
Energy input = Energy stored + Mechanical energy
Mechanical energy = Energy input — Energy stored
Substracting (2) from (1),
Mechanical energy = liz dL; +} 13412 i; 12 dM
The self inductances ہا and ہا are constants and hence dL,;and dL, are zero.
स Mechanical energy = i; iz dM
If Tj is the instantaneous deflecting torque and 30 is the change in the deflection
then
Mechanical energy = Mechanical work done
= Ti do
7 12 d M = Ti d 9
T; = iy ig SN
This is the expression for the instantaneous deflecting torque. Let us see its
operation on a.c. and d.c.
D.C. operation : For d.c. currents of I; and 12,
aM
Ta = 1112 a0
The controlling torque is provided by springs hence
T = KO
In steady state, Ty ടനം
dM
I, Iz ठठ = 1; 0
൫ سے [12 dM
K 988
Thus the deflection is proportional to the product of the two currents and the rate
of change of mutual inductance.
A.C, operation;: In a.c. operation, the total deflecting torque over a cycle must be
obtained by integrating 11. over one period.
Average deflecting torque over one cycle is,
it
Ta = பய dit
T = Time period of one cycle
dM 1. .
Ta = وق ٣٣ di