Solution: Let 1 = length of AB
॥ = Reduced bearing of AB
Latitude of AB = The difference between the north coordinate of A and B

= 840.78 - 25
= 325.53 4

Departure of AB = The difference beiween the east 6
௩31560 - 640,75
= -325.15

00161131 of A and B

latitude
325,15
—

M053 | 2 marks |
= 4

6٥۱
Since the latitude is (+)ve and the departure is )-(۷۴۰ the line AB

ட்ப ۵۵۵۷
RB. of AB ۰۷۷٣۷ nh (N.W.) quadrant. 2 marks
WCB of AB = 360° - 43° ‏“ب‎

= 316° 19“

Length of line AB = ४1: + 0: k
‏ہے‎ 2 marks
तत
= 04033 + (32515
= 470.834 m