APJ ABDUL KALAM TECHNOLOGICAL UNIVERSITY Previous Years Question Paper & Answer

Course : B.Tech

Semester : SEMESTER 3

Year : 2022

Term : JANUARY

Scheme : 2015 Full Time

Course Code : CE 201

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08000CE201122001

concentrated load of 20 kN at mid span. Determine the maximum bending stress
and sketch the stress distribution.

Draw the shear stress distribution for an isosceles triangular cross section and
mark the salient points

Draw the shear force and bending moment diagram of the simply supported
beam AB shown in Fig.1. Mark the salient values. Also find maximum bending
moment.

2kN/m 6kN 3kN/m
(2-3
A B
#
2m lm lm 2m
Fig.1
Describe with neat sketch ‘beams of uniform strength’.
PART C

Answer any two full questions, each carries 20 marks.
Differentiate between long column and short column.

A shaft transmits a power of 60kW at 100 rpm. If the shaft has solid circular
cross section, find the minimum diameter required assuming the angle of twist is
limited to 0.5 per meter length of the shaft. Also determine the diameter of a
hollow shaft with diameter ratio of 0.75. Given G= 80GPa.

State Moment- Area theorems

Derive Rankine’s formula for finding the critical load of columns.

At a point in a stressed material, the normal stress on a plane is 50 पाणा (ग)
and a normal stress of 30 N/mm* (C) is acting on the plane perpendicular to the
given plane. The shear stress acting on these planes is 25 N/mm”. Determine the
principal stresses and their planes using Mohr’s circle. Also determine the
maximum shear stress at that point.

A 2m long thin cylindrical shell (both ends closed), internal diameter 90cm and
thickness 12mm, is subjected to internal pressure 2N/mm/?. Find 1) hoop and
longitudinal stresses 2) changes in diameter and length shell. Take E =
2x10°N/mm/? and Poisson’s ratio = 0.3.

A steel column made of a 4 m long hollow circular section, having 300 mm
internal diameter and 20 mm thick, is fixed at both the ends. Determine the safe
axial load the column can carry with a factor of safety 3.5 using Euler’s formula.
E=2.1x10° N/mm?

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