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Reg No.:_ Name:

APJ ABDUL KALAM TECHNOLOGICAL UNIVERSITY
SIXTH SEMESTER B.TECH DEGREE EXAMINATION(S), DECEMBER 2019

Course Code: ME304
Course Name: DYNAMICS OF MACHINERY
Max. Marks: 100 Duration: 3 Hours
PARTA
Answer any three full questions, each carries 10 marks. Marks
1 The dimensions of a four-link mechanism are: AB = 400mm, BC = 600mm, (7) (10)

= 500mm, AD = 900 mm and ZDAB = 609. AD is the fixed link. E is a point on
the link BC such that BE = 400mm and CE = 300mm (BEC clockwise). A force
of 150 245° N acts on DC at a distance of 250mm from D. Find the required
input torque on the link AB for static equilibrium of the mechanism.
2 A Slider-crank mechanism as shown in figure is given below. The force acting (10)
on slider is 8000 N. Calculate the driving torque. The dimensions of links are:

OA = 200 mm ; AB = 800 mm and ZBOA = 602

Slider
LINK 4(PISTON)

FIXED LINK 1 FIXED LINK 1

3 Derive an expression for the velocity and acceleration of a piston of a slider crank (10)
mechanism and the inertia force due to reciprocating mass.
4 In a vertical IC engine, the connecting rod is 4.5 times the crank. The mass of the (10)
reciprocating parts is 1.20kg and the stroke of the piston is 140mm. The engine runs
at 2000 rpm. If the net load on the piston due to gas pressure is 2124 when the crank
has turned through an angle of 60° from the top dead centre, determine the
(i) Thrust in the connecting rod, (ii)Thrust on the piston walls, (iii)Tangential

force on the crank pin, (iv)Torque on the crankshaft

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